Drawing a first red ball: A
Drawing a second red ball: B
Probability of drawing two red balls: P(A ∩ B)=0.310
Probability of drawing a red ball first: P(A)=0.916
Probability of drawing a second red ball given that the first ball drawn was red: P(B\A)=?
P(B\A)=P(A ∩ B) P(A)→
P(B\A)=(0.310)(0.916)→
P(B\A)=0.28396→
P(B\A)=0.284
Answer: The probability of drawing a second red ball, given that the first ball drawn was red is 0.284
