Answers:
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Question # 1) from first graph:
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The answer is: " 3 " .
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→ [tex] \frac{AD}{AB} [/tex] ; in "simplest form" , is: " 3 " .
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Question #2) from second graph:
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The answer is: " 4 " .
_____________________________________________________ → " (the slope of BE) over (the slope of AE) " ;
that is: " (the slope of BE) / (the slope of AE) " ;
in "simplest form" , is: " 4 " .
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Explanation:
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For Question #1)
AD = 9 units (counted from the "attached graph").
AB = 3 units (counted from the "attached graph").
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We are asked to write: "AD over AB" ; in "simplest form" ;
→ AD/AB = " 9/3 " = " (9÷3) / (3÷3) " = "(3/1)" = " 3 ÷ 1 " = 3 .
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→ The answer is: " 3 " .
_____________________________________________________ → "AD over AB" ; in "simplest form" ; is: " 3 " .
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→ AD/AB = " 3 " .
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Question 2): From second graph:
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Find the: " (slope of BE) / (slope of AE) " ; in "simplest form" :
From examination of the "second graph attached" :
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The "slope of BE" = rise/ run = 5/1 .
The "slope of AE" = rise/ run = 5/4 .
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So: "(the slope of BE) / (the slope of AE) ;
= (5/1) / (5/4) ;
= [tex] \frac{5}{1} [/tex] ÷ [tex] \frac{5}{4}[/tex] ;
→ To divide a fraction, you multiply the "reciprocal of the fraction; as follows:
= [tex] \frac{5}{1} [/tex] * [tex] \frac{4}{5}[/tex] ;
→ Both " 5 's " cancel out to " 1 "; since: "{5 ÷ 5 = 1 }" ;
→ And we can rewrite as:
= [tex] \frac{1}{1} [/tex] * [tex] \frac{4}{1}[/tex] ;
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= 1 * 4 ;
= " 4 " .
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→ The answer is: " 4 " .
___________________________________________________________ → "AD over AE" ; in "simplest form" ; is: " 4 " .
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