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A projectile is launched with the velocity of 100 meters/second and at an angle 45° from horizontal. If the projectile's hang time is 14.43 seconds, what is its range?

Respuesta :

olemakpadu
Range = Horizontal Component of Velocity * time

R =  uCosθ  * time.                  u = 100m/s, θ = 45°, time = 14.43

R = 100Cos45° * 14.43     Use your calculator.

Range = 1020.4m
nimacarra77

Answer:

1020m

Explanation:

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