From the 6 male and 10 female sales representatives for an insurance company, a team of 3 men and 2 women will be selected to attend a national conference on insurance fraud. In how many ways can the team of 5 be selected?

We'll find the answer by multiply "6 choose 3" by "10 choose 2". Let the number of ways we can choose be w.

w = C(6, 3) * C(10, 2)
We can use this formula to solve the combinations.
[tex]C(n, r) = \frac{n!}{r!(n-r)!} [/tex]
w = 20 * 45
w = 900

So there are 900 ways to create a group of people to go to the conference.

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From the 6 male and 10 female sales representatives for an insurance​ company, a team of 3 men and 2 women will be selected to attend a national conference on insurance fraud. In how many ways can the team of 5 be​ selected?

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From the 6 male and 10 female sales representatives for an insurance company, a team of 3 men and 2 women will be selected to attend a national conference on insurance fraud. In how many ways can the team of 5 be selected?