Calculate the indefinite integral : (assume t > a and t >
b. use c for the constant of integration.) t (t −a) (t −
b.dt

Respuesta :

So here's your problem: [tex] \int\limits {[t(t-a)(t-b)]} \, dt [/tex].  The easiest way to do this is to distribute that whole thing out by FOIL-ing to get [tex] \int\limits {t^3-t^2b-t^2a+abt} \, dt [/tex].  Now the integration is straightforward. We are integrating with respect to t, so treat a and b like "regular" numbers.  Your integration, before simplifying, is [tex] \frac{t^4}{4}- \frac{bt^3}{3}- \frac{at^3}{3}+ \frac{abt^2}{2} [/tex].  Those 2 terms in the middle have the same denominator and power on the t, so we will combine those as like to get [tex] \frac{t^4}{4}- \frac{abt^3}{3}+ \frac{abt^2}{2}+C [/tex]