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A 76 ​-ton monolith is transported on a causeway that is 2500 feet long and has a slope of about 3.4 degrees. how much force parallel to the incline would be required to hold the monolith on this​ causeway?

Respuesta :

We can say that the force required to hold the monolith is same as the component of weight along the inclined plane

[tex]F = mgsin\theta[/tex]

here we have

m =76 ton = 68946 kg

[tex]\theta = 3.4 degree[/tex]

now force required to hold this

[tex]F = mgsin\theta[/tex]

[tex]F = 68946*9.8*sin3.4[/tex]

[tex]F = 40071.6 N[/tex]

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