Answer:
He went over by 5/12 of a cup
Step-by-step explanation:
Consider the provided information.
The recipe says that he has to mix 32 grams of vanilla powder to the flour.
Jeff knows that 1 cup of that particular vanilla powder has a mass of 128 grams. He added 2/3= of a cup of vanilla powder to the flour.
[tex]\frac{2}{3} \cdot 128=\frac{256}{3}=85\frac{1}{3}[/tex]grams.
That means he added [tex]85\frac{1}{3}[/tex] grams of vanilla but he needs to add only 32 grams of vanilla.
Now find how much he added more.
[tex]85\frac{1}{3}-32=53\frac{1}{3}[/tex] grams.
That means he added [tex]53\frac{1}{3}[/tex] grams more vanilla powder.
Lets find [tex]53\frac{1}{3}[/tex] is how much of a cup.
If we multiply [tex]\frac{5}{12}[/tex] with 128 we will get:
[tex]\dfrac{5}{12}\cdot 128=\dfrac{5\cdot 128}{12}=\dfrac{5\cdot 32}{3}=\dfrac{160}{3}=53\dfrac{1}{3},[/tex]
Hence, He went over by 5/12 of a cup
