A bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. during the first part, she rides for 22 minutes at an average speed of 7.2 m/s. during the second part, she rides for 36 minutes at an average speed of 5.1 m/s. finally, during the third part, she rides for 8.0 minutes at an average speed of 13 m/s.
a. how far has the bicyclist traveled during the entire trip?
b. what is her average velocity for the entire trip?

during the first part, she rides for 22 minutes at an average speed of 7.2 m/s. during the second part, she rides for 36 minutes at an average speed of 5.1 m/s. finally, during the third part, she rides for 8.0 minutes at an average speed of 13 m/s.

total distance in first part

[tex]d_1 = 22*60 * 7.2 = 9504 m[/tex]

total distance in second part

[tex]d_2 = 36*60 * 5.1 = 11016 m[/tex]

total distance in third part

[tex]d_3 = 8 * 60 * 13 = 6240 m[/tex]

so total distance would be

[tex] d = 9504 + 11016 + 6240 = 26760 m[/tex]

part b)

average velocity is given as

[tex]v = \frac{displacement}{time}[/tex]

[tex]v = \frac{26760}{(22 + 36 + 8)*60}[/tex]

[tex]v = 6.76 m/s[/tex]

so average velocity is 6.76 m/s