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Consider the reaction, 2 d(g) + 3 e(g) + f(g) => 2 g(g) + h(g) when e is decreasing at 0.16 mol/ls, how quickly is g increasing? give your answer to 3 decimal places.

Respuesta :

2d(g) + 3e(g) + f(g) -------> 2g(g) + h(g)

As it can be seen from the equation that for every 3 moles of e consumed,=2 moles of g formed.

for every 1 moles of e consumed =[tex]\frac{2}{3}[/tex] moles of g formed  

So, if e is decreasing at a rate of 0.16 mol s⁻¹

[tex]=\frac{2}{3}\times0.16 = 0.106 mol s^{-1}[/tex]

So when e is decreasing at 0.16 mol s⁻¹,  g is increasing at a rate of 0.106 mol s⁻¹.

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