Find the LCD of 3/5 and 1/6.
a. 5B. 6C. 11D. 302. what is the difference between 3/7 and 1/14.
a. 1\2B. 4/14C. 5/14D. 9/143. if Sandy's cookie recipe calls for 1/3 cup of brown sugar and she increases it by 2/9 of a cup, how much brown sugar does she use?
a. 7/9 cupB. 5/9 cup
c. 4/9 cupD. 1/9 cup4. what value could be added to 2/15 to make the sum greater than 1/2?
a. 1/15B. 8/30C. 5/15D. 8/15 5. which set of mixed numbers has a difference less than 1?
a. 1 2/9, 1 1/9B. 3 4/7, 2 1/7C. 2 4/5, 1 1/3D. 2 7/9, 1 1/3

Respuesta :

Question 1:

We have to find the LCD of [tex]\frac{3}{5}[/tex] and [tex]\frac{1}{6}[/tex]

LCD is the least common denominator is the lowest common multiple of the denominators of a set of fractions.

Here the denominators are 5 and 6.

So, we will find the LCM of 5 and 6

5 = [tex]5 \times 1[/tex]

6 = [tex]2 \times 3[/tex]

LCM of 5 and 6 = [tex]2 \times 3 \times 5[/tex]

= 30

Therefore, the LCD of these numbers is 30.

Question 2:

We have to find the difference between  [tex]\frac{3}{7}[/tex]  and  [tex]\frac{1}{14}[/tex].

Difference = [tex]\frac{3}{7}- \frac{1}{14}[/tex]

LCM of 7 and 14 is 14

Therefore, difference = [tex]\frac{6-1}{14}[/tex]

= [tex]\frac{5}{14}[/tex]

Question 3:

Amount of brown sugar used by Sandy = [tex]\frac{1}{3}[/tex]

Amount of sugar increased by Sandy = [tex]\frac{2}{9}[/tex]

Total amount of Sugar used by Sandy = [tex]\frac{1}{3}+\frac{2}{9}[/tex]

LCM of 3 and 9 is 9.

Total amount of Sugar used = [tex]\frac{3+2}{9}[/tex]

= [tex]\frac{5}{9}[/tex] cup

Question 4:

Let the number which should be added to [tex]\frac{2}{15}[/tex] to make the sum greater than [tex]\frac{1}{2}[/tex] be 'x'

So, [tex]\frac{2}{15}+x >\frac{1}{2}[/tex]

[tex]x > \frac{1}{2}-\frac{2}{15}[/tex]

LCM of 2 and 15 is 30.

[tex]x>\frac{15-4}{30}[/tex]

[tex]x>\frac{11}{30}[/tex]

So, the number is [tex]\frac{11}{30}[/tex]

Question 5:

We have to identify the set of mixed numbers has a difference less than 1.

Set 1: [tex]1 \frac{2}{9}[/tex] and [tex]1 \frac{1}{9}[/tex]

Difference = [tex]1 \frac{2}{9}-1 \frac{1}{9}[/tex]

= [tex]\frac{11}{9}- \frac{10}{9}[/tex]

= [tex]\frac{1}{9}[/tex]

This set has difference less than 1.

Set 2:

[tex]3 \frac{4}{7}[/tex] and [tex]2 \frac{1}{7}[/tex]

Difference = [tex]3 \frac{4}{7}-2 \frac{1}{7}[/tex]

= [tex]\frac{25}{7}- \frac{15}{7}[/tex]

= [tex]\frac{10}{7}[/tex]

This set does'not have difference less than 1.

Set 3:

[tex]2 \frac{4}{5}[/tex] and [tex]1 \frac{1}{3}[/tex]

Difference = [tex]2 \frac{4}{5}-1 \frac{1}{3}[/tex]

= [tex]\frac{14}{5}- \frac{4}{3}[/tex]

= [tex]\frac{42-20}{15}[/tex]

= [tex]\frac{22}{15}[/tex]

This set does'not have difference less than 1.

Set 4:

[tex]2 \frac{7}{9}[/tex] and [tex]1 \frac{1}{3}[/tex]

Difference = [tex]2 \frac{7}{9}-1 \frac{1}{3}[/tex]

= [tex]\frac{25}{9}- \frac{4}{3}[/tex]

= [tex]\frac{13}{9}[/tex]

This set does'not have difference less than 1.