Initial volume of the balloon = [tex]V_{1}[/tex]= 348 mL
Initial temperature of the balloon [tex]T_{1}[/tex] = [tex]25.0^{0}C + 273 = 298 K[/tex]
Final volume of the balloon [tex]V_{2}[/tex] = 322 mL
Final temperature of the balloon = [tex]T_{2} = ?[/tex]
According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.
[tex]\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }[/tex]
On plugging in the values,
[tex]\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }[/tex]
[tex]T_{2} =276 K[/tex]
Therefore, the temperature of the freezer is 276 K
