Respuesta :
Explanation:
[tex]4MnCO_3+O_2\rightarrow 2Mn_2O_3 + 4CO_2[/tex]..(1)
Manganese (II) carbonate and oxygen reacts to give manganses (III) oxide with carbon-dioxide gas.
[tex]Mn_2O_3+ 2Al\rightarrow Al_2O_3+ 2Mn[/tex]..(2)
Manganese (III) oxide reacts with aluminum metal to give aluminum oxide and manganese metal
On adding (1) and 2[tex]\times [/tex](2) we will get the net net chemical equation for the production of manganese. So,
The net balanced equation we got:
[tex]4MnCO_3+O_2+4Al\rightarrow 2Al_2O_3+ 4Mn+4CO_2[/tex]
The net chemical equation for production of manganese is [tex]\boxed{{\text{4MnC}}{{\text{O}}_{\text{3}}} + {{\text{O}}_{\text{2}}} + {\text{4Al}} \to {\text{2A}}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}} + {\text{4Mn}} + {\text{4Al}}}[/tex].
Further Explanation:
Balanced chemical reaction:
The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.
Stoichiometry of a reaction is used to determine the amount of species present in the reaction by the relationship between the reactants and products. It can be used to determine the moles of a chemical species when the moles of other chemical species present in the reaction is given.
Consider the general reaction,
[tex]{\text{A}} + 2{\text{B}}\to3{\text{C}}[/tex]
Here,
A and B are reactants.
C is the product.
The production of manganese from manganese (II) carbonate, oxygen, and aluminium occurs in two steps.
In the first step, manganese carbonates react with oxygen to form manganese(III)oxide and carbon dioxide.
The balanced chemical equation for formation of manganese(III)oxide is as follows:
[tex]{\text{4MnC}}{{\text{O}}_{\text{3}}} + {{\text{O}}_{\text{2}}} \to{\text{2M}}{{\text{n}}_{\text{2}}}{{\text{O}}_{\text{3}}} + {\text{CO}}{ & _{\text{2}}}[/tex]
......(1)
In the second step, manganese (III) oxide reacts with aluminium metal to form manganese metal and aluminium oxide.
The balanced chemical equation for formation of aluminium oxide is as follows:
[tex]{\text{M}}{{\text{n}}_{\text{2}}}{{\text{O}}_{\text{3}}} + {\text{2Al}} \to {\text{A}}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}} + {\text{2Mn}}[/tex] ......(2)
Multiply equation (2) by 2. The equation (2) will become,
[tex]{\text{2M}}{{\text{n}}_{\text{2}}}{{\text{O}}_{\text{3}}} + 4{\text{Al}}\to2{\text{A}}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}}+4{\text{Mn}}[/tex] ......(3)
On adding equation (1) and equation (3), the net chemical equation for the production of manganese is as follows:
[tex]{\text{4MnC}}{{\text{O}}_{\text{3}}}+{{\text{O}}_{\text{2}}}+{\text{4Al}} \to {\text{2A}}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}} + {\text{4Mn}} + {\text{4Al}}[/tex]
Learn more:
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Answer details:
Grade: High School
Subject: Chemistry
Chapter: Balanced chemical equation
Keywords: Manganese, 4Mn, 2Al, stoichiometry, number of atoms, balanced chemical reaction.
