Respuesta :

gmany

The equation of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

(h, k) - center

r - radius

We have:

[tex](x-2)^2+(y+3)^2=16\\\\(x-2)^2+(y-(-3))^2=4^2[tex]

Therefore:

[tex]h=2,\ k=-3\to\text{center:}\ (2,\ -3)\ \text{and}\ r=4[/tex]


Ver imagen gmany

The graph matches the circle defined by this equation (x-2)^2 + (y+ 3)^2 = 16 is option D.

What is the equation of the circle with radius r units, centered at (x,y) ?

If a circle O has radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane,

then its equation is given as:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

The given equation of the circle is;

[tex](x-2)^2 + (y+ 3)^2 = 16[/tex]

Where, (h, k) - center

r - radius

here the radius of the circle is 4.

So, the graph matches the circle defined by this equation (x-2)^2 + (y+ 3)^2 = 16 is option D.

Learn more about equation of a circle here:

https://brainly.com/question/10165274

#SPJ2

Otras preguntas