Respuesta :
The archer is fired horizontally.
It hits the target which is at 100 m distance.
The horizontal velocity of the archer is always constant for a projectile in this situation.
The total time of flight is given as 2.2 s
Let the initial velocity is u .
Hence the target distance = ut
⇒ 100 m = u×2.2 s
⇒u = 100÷2.2 m/s
=45.45 m/s
We are asked to calculate the vertical distance travelled.
The vertical distance travelled is calculated as-
[tex]s= ut +\frac{1}{2} at^2[/tex] [ s is the distance and a is the acceleration]
[tex]s = 0*2.2 -\frac{1}{2} g[2.2]^2[/tex] [g is te acceleration due to gravity]
[tex]s=\frac{1}{2} 9.8*[2.2]^2[/tex] [here we have taken only magnitude]
=23.716 m [ans]
