Here we are given the expression:
[tex](b-2ya^{2})(3b-3ya^{2})[/tex]
We will use foil method to solve this expression.
The word FOIL is an acronym for the four terms of the product:
First ("first" terms of each binomial are multiplied together)
Outer ("outside" terms are multiplied—that is, the first term of the first binomial and the second term of the second)
Inner ("inside" terms are multiplied—second term of the first binomial and first term of the second)
Last ("last" terms of each binomial are multiplied)
Using this method let us simplify our expression.
[tex](b-2ya^{2})(3b-3ya^{2})[/tex]
=[tex]3b^{2}-3bya^{2}-6bya^{2}+6y^{2}a^{4}[/tex]
Now combining like terms we have:
=[tex]3b^{2}-9bya^{2}+6y^{2}a^{4}[/tex]
Answer: [tex](b-2ya^{2})(3b-3ya^{2})[/tex] simplifies to [tex]3b^{2}-9bya^{2}+6y^{2}a^{4}[/tex]
Answer:
The answer is 3b² - 9bya² - 6y²a².
Explanation:
(b - 2ya²)(3b-3ya²)
3b² - 3bya²-6bya²-6ya²
3b² - 9bya² - 6y²a².
Answer would be 3b² - 9bya² - 6y²a².
