Respuesta :
Using the combined gas law of P1V1=P2V2 and plug it in you get (4)V1 for you don't have initial volume = (0.2)(500) --> 4V1=100, divide by the coefficient on both sides and you get V1=25
Answer:
[tex]25L[/tex]
Explanation:
The problem can be solved using Boyle's law for the volume and pressure of a gas at constant temperature:
[tex]P_{1}V_{1}=P_{2}V_{2}[/tex]
Where the quantities with sub-index 1 are the initial conditions for the gas and the quantities with sub-index 2 are for the final conditions of the gas.
We want to know the initial volume, this is:
[tex]V_{1}=\frac{P_{2}V_{2}}{P_{1}}[/tex]
we also know from the problem that
[tex]P_{1}=4atm\\P_{2}=0.2atm\\V_{2}=500L[/tex]
Thus, the initial volume V1 is:
[tex]V_{1}=\frac{0.2atm*500L}{4atm}[/tex]
[tex]V_{1}=25L[/tex]
