Answer:
12.1
Step-by-step explanation:
We use the formula for the distance between two arbitrary points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] in the xy-coordinate plane, that is:
[tex]d=\sqrt{(x_1-x_2)^2 + (y_1-y_2)^2}[/tex]
So, replacing the points [tex]M=(2,16)[/tex] and [tex]M_2=(-3,5)[/tex], we obtain:
[tex]d=\sqrt{(2-(-3))^2 + (16-5)^2}\\d=\sqrt{(2+3)^2 + (16-5)^2}\\d=\sqrt{5^2 + 11^2}\\d=\sqrt{146 }=12.083045... \simeq 12.1[/tex]
that is the answer.
note: observe that we only use the coordinates between the two midpoints and not the point J.
