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Use standard enthalpies of formation to determine for: 2al(s) + 3cl2(g) → 2alcl3(s) enter in kj. find the change in internal energy for this reaction. enter in kj.

Respuesta :

Hey there!:

Al= 0 Kj

Cl2 = 0 kj

Aluminium Chloride Solid AlCl3  = 705.63 KJ

Therefore:

enthalpy of formation is :

2*(-705.63 KJ) = 1411.26 KJ


Hope that helps!

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