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In the resonance structure with the electron geometry "c tetrahedral; 1st n trigonal planar; 2nd n linear" would you expect the two nitrogen-nitrogen bond angles and bond lengths to be the same or different?

Respuesta :

Hey there!:

*Since 1st N is trigonaplanar which indicates sp2 hybridized N and bond angle will be 120º  .


*Thus C-N-N bond angle is 120º  .

*Since 2nd N is said to have linear we get N-N-N  bond angle 180º .


Now as we have resonance both N1-N2 and N2-N3  will have equal lengths .


Hope that helps!

Answer:

  • The 1st n trigonal planar will be sp2 hybridized and the bond angle will be equal to 120°.
  • There for the angle between Carbon-Nitrogen-Nitrogen bond is 120°.
  • The 2nd n is linear which means that we will get 180° bond angle for n-n-n and as we have resonance that will make bond length for n1-n2 and n2-n3 equal.

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