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How many moles of gas does it take to occupy 120 L at a pressure of 233 kPa and a temperature of 340 K?

A. 6.4 moles
B. 7.7 moles
C. 8.6 moles
D. 9.9 moles

Respuesta :

A would be correct have a nice day.

Answer:

The correct answer is option D.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 233 kPa

1 atm = 101.325 kPa

[tex]233kPa=\frac{233}{101.325} atm=2.30 atm[/tex]

V = Volume of gas = 120 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 340 K

Putting values in above equation, we get:

[tex]2.30 atm\times 120L=n\times (0.0821L.atm/mol.K)\times 340K\\\\n=9.88 mole\approx 9.9 mole[/tex]