makaliaweber64
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The graph above represents the following polynomial function.


f(x) =x^3- 2x^2 -3x
What are the solutions to the function?
A.
x = -3, x = -1, and x = 0
B.
x = -3, x = 0, and x = 1
C.
x = -1, x = 0, and x = 3
D.
x = 0, x = 1, and x = 3

Respuesta :

Answer:

C. 0, -1, 3

Step-by-step explanation:

Note: There is no graph. I assume you mean "zeroes/roots" by "solutions".

x(x^2-2x-3)=0

/(x^2-2x-3)

x=0


x^2-2x-3 = x^2+x-3x-3 = x(x+1) + ( -3(x+1) = (x-3)(x+1)

/(x-3) --> x +1 =0, x=-1

/(x+1) --> x-3 = 0, x=3


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