Answer: C
Step-by-step explanation:
∑ 8([tex]\frac{7}{3}[/tex])⁽ⁿ⁻¹⁾ from n = 1 to n = 5
n = 1 → 8([tex]\frac{7}{3}[/tex])⁽¹⁻¹⁾
= 8 = [tex]\frac{648}{81}[/tex]
n = 2 → 8([tex]\frac{7}{3}[/tex])⁽²⁻¹⁾
= [tex]\frac{56}{3}[/tex] = [tex]\frac{1512}{81}[/tex]
n = 3 → 8([tex]\frac{7}{3}[/tex])⁽³⁻¹⁾
= [tex]\frac{392}{9}[/tex] = [tex]\frac{3528}{81}[/tex]
n = 4 → 8([tex]\frac{7}{3}[/tex])⁽⁴⁻¹⁾
= [tex]\frac{2744}{27}[/tex] = [tex]\frac{8232}{81}[/tex]
n = 5 → 8([tex]\frac{7}{3}[/tex])⁽⁵⁻¹⁾
= [tex]\frac{19208}{81}[/tex] = [tex]\frac{19208}{81}[/tex]
Sum = [tex]\frac{33128}{81}[/tex]
= 408.99
