Respuesta :
v = speed of motion = 3530 km/h = 3530 (1000/3600) m/s = 980.6 m/s
consider the motion when the angle with the horizontal is 15 deg :
[tex]v_{oy}[/tex] = component of velocity along vertical direction = v Sin15 = 980.6 Sin15 = 253.8 m/s
[tex]v_{ox}[/tex] = component of velocity along horizontal direction = v Cos15 = 980.6 Sin15 = 947.2 m/s
t = time of travel = 20 sec
X = displacement along the x-direction
Y = displacement along the Y-direction
Horizontal displacement in first 20 sec is given as
X = [tex]v_{ox}[/tex] t
X = 947.2 x 20
X = 18944 m
vertical displacement in first 20 sec is given as
Y = [tex]v_{oy}[/tex] t
Y = 253.8 x 20
Y = 5076 m
consider the motion when the angle with the horizontal is 35 deg :
[tex]v'_{oy}[/tex] = component of velocity along vertical direction = v Sin35 = 980.6 Sin35 = 562.4 m/s
[tex]v'_{ox}[/tex] = component of velocity along horizontal direction = v Cos35 = 980.6 Sin35 = 803.3 m/s
t = time of travel = 10 sec
X' = displacement along the x-direction
Y' = displacement along the Y-direction
Horizontal displacement in next 10 sec is given as
X' = [tex]v'_{ox}[/tex] t
X' = 803.3 x 10
X' = 8033 m
vertical displacement in next 10 sec is given as
Y' = [tex]v'_{oy}[/tex] t
Y' = 562.4 x 10
Y' = 5624 m
X'' = total horizontal displacement
Y'' = total vertical displacement
Total horizontal displacement is given as
X'' = X + X' = 18944 + 8033 = 26977 m
Total vertical displacement is given as
Y'' = Y + Y' = 5076 + 5624 = 10700 m
Total gain in altitude = Y'' = 10700 m
total horizontal displacement = X'' = 26977 m
resultant displacement using pythagorean theorem is given as
R = sqrt(X''² + Y''²)
R = sqrt((26977)² + (10700)²)
R = 29021.5 m
