The triangle has sides a,b,c such that
a = 2*sqrt(5), b = sqrt(5), and c = 2*sqrt(10)
Square each value
a = 2*sqrt(5)
a^2 = (2*sqrt(5))^2
a^2 = 2^2(sqrt(5))^2
a^2 = 4*5
a^2 = 20
b^2 = 20 for similar reasons as side 'a'
c = 2*sqrt(10)
c^2 = (2*sqrt(10))^2
c^2 = 2^2*(sqrt(10))^2
c^2 = 4*10
c^2 = 40
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Using the pythagorean theorem, we see that
a^2 + b^2 = c^2
20 + 20 = 40
40 = 40
So the initial equation a^2 + b^2 = c^2 is true making the triangle with sides a,b,c defined above to be a right triangle
Answer:
(2 * sq root 5)^2 = 20
20 + 20 = 40
2*sq root(10)^2 = 40
The sum of both sides squared = hypotenuse squared.
By the Pythagorean Theorem, we know that this is a right triangle.
Step-by-step explanation:
