Answer:
[tex]x^{2}(x+4)+5(x+4)\\(x^{2} +5)(x+4).[/tex]
Step-by-step explanation:
In order to be able to determine the facts of [tex]x^{3}+4x^{2} +5x +20[/tex]
you just have ti group and search for a term in common that could help you factorize into two separated terms, first, you try and factorize the first two terms:
[tex]x^{3}+4x^{2} \\x^{2} (x+4)[/tex]
Remember always trying to take out the maximum exponential possible, in this case we were able to withdraw the [tex]x^{2}[/tex] and this helps us to factorize easier the second one since we already have a term that we want to have in common whic wuold be (x+4):
[tex]5x+20\\5(x+4)[/tex]
Now we just put together the [tex]x^{2}[/tex] and the 5, and we multiply it by our common factor:
[tex](x^{2} +5)(x+4).[/tex]
