Answer:
for the function f(x) =x²-4x-12 can be written as y=x²-4x-12
A) X-intercept= the value of y when y is zero thus we have 0=x²-4x-12 thus we solve the equation: x²-4x-12=0 we look for roots i.e two numbers whose sum is -4 and product is -12 and the two numbers are -6 and 2
x²-6x+2x-12=0
x(x-6)+2(x-6)=0 so x-6=0 or X+2=0 thus x- intercept are two 6 and -2
b)y-intercept and this is the value of y where x is zero
And if x=o, y=0²-4*0-12=-12 thus y-intercept=-12
c)maximum and minimum are points where y value is zero.
from part a thus maximum is when x=6 and y=6²-4*6-12=0 and other point is when x= -2, y= -2²-4*-2-12 =0 thus minimum FOR more clarification,explanation and further solutions cotact me at my g mail.com i.e patostats@
