Respuesta :

Answer:

Choice B is correct

Step-by-step explanation:

The first step would be to factorize the expression;

[tex]2a^{2} -11a+14[/tex]

To do this we have to determine two numbers whose product is 2(14) =28 and sum -11. By trial and error the two numbers are -7 and -4. We then substitute this two numbers in place of -11 in the expression to obtain;

[tex]2a^{2}-4a-7a+14\\ 2a(a-2)-7(a-2)\\(2a-7)(a-2)[/tex]

The product now becomes;

[tex]\frac{2a-7}{a} *\frac{3a^{2} }{(2a-7)(a-2)}\\\frac{3a}{a-2}[/tex]

zainebamir540

Answer:

Choice b is the answer.

Step-by-step explanation:

We have given two expression.

[tex]\frac{2a-7}{a}.\frac{3a^{2} }{2a^{2}-11a+14 }[/tex]

We have to find their product.

[tex]\frac{2a-7}{a}.\frac{3a^{2} }{2a^{2}-7a-4a+14 }[/tex]

[tex]\frac{2a-7}{a}.\frac{3a.a}{a(2a-7)-2(2a-7)}[/tex]

[tex]\frac{2a-7}{a}.\frac{3a.a}{(2a-7)(a-2)}[/tex]

[tex]\frac{2a-7}{2a-7}.\frac{3a.a}{a}.\frac{1}{a-2}[/tex]

[tex]\frac{3a}{a-2}[/tex] which is the answer.

Otras preguntas