Answer:
So the factors are (y + 1)(y + 4/3)
Step-by-step explanation:
Given in the question an equation
3y² + 7y + 4
To find it's factor we will use quadratic formula
y = -b ± √(b²-4(a)(c)) / 2a
here a = 3
b = 7
c = 4
y1 = -7 + √(7²- 4(3)(4)) / 2(3)
= -7 + √49 - 48 / 6
= -7 + 1 /6
= -6/6
= -1
y2 = -7 - √(7²- 4(3)(4)) / 2(3)
= -7 - √49 - 48 / 6
= -7 - 1 /6
= -8/6
= -4/3
So the factors are (y + 1) and (y + 4/3)
