Answer:
A. all three rectangular faces have the same surface area
B. the surface area of each rectangular face is [tex]66\ cm^{2}[/tex]
D. the surface area of one base is [tex]15.6\ cm^{2}[/tex]
Step-by-step explanation:
Verify each statement
case A) all three rectangular faces have the same surface area
The statement is true
Because, the equilateral triangle has the three equal sides and the three equal internal angles.
case B) the surface area of each rectangular face is [tex]66\ cm^{2}[/tex]
The statement is true
Because, the area of each rectangular face is equal to
[tex]6(11)=66\ cm^{2}[/tex]
case C) the combined surface area of both bases is greater than the surface area of one rectangular face
The statement is False
Because
The combined surface area of both bases is [tex]2[\frac{1}{2}(6)(5.2)]=31.2\ cm^{2}[/tex]
The surface area of one rectangular face is [tex]66\ cm^{2}[/tex]
therefore
[tex]31.2\ cm^{2}< 66\ cm^{2}[/tex]
case D) the surface area of one base is [tex]15.6\ cm^{2}[/tex]
The statement is True
Because
The surface area of one base is [tex]\frac{1}{2}(6)(5.2)=15.6\ cm^{2}[/tex]
