Answer:
[tex]1,715\ in^{2}[/tex]
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> surface area of the enlarged figure
y----> surface area of the original figure
[tex]z^{2}=\frac{x}{y}[/tex]
we have
[tex]z=7[/tex]
[tex]y=35\ in^{2}[/tex]
substitute
[tex]7^{2}=\frac{x}{35}[/tex]
[tex]x=7^{2}(35)=1,715\ in^{2}[/tex]
