Answer:
A. 1.51 seconds
B. 7.26 meters
Explanation:
A. Time to reach 22 meters
Find horizontal component of initial velocity V = 19 m/s:
Vx= Vcos(theta) = 19cos(40) = 14.55 m/s
Use equation d= V0t + (1/2)at^2 to find the time
(acceleration is 0 for horizontal component) so: d = Vx*t
t = d/Vx = 22/14.55 = 1.51 seconds
B. Find vertical component of initial velocity:
Vy= Vsin(theta) = 19sin(40) = 12.21
Use equation y = V0*t + (1/2)at^2 to find the height at 1.51 seconds
y = (12.21)(1.51) + (.5)(-9.81)(1.51)^2
y= 7.26 meters
