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The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). if an object fell 64 ft in 8 seconds, how far will it have fallen by the end of 9 seconds

Respuesta :

AL2006

If the distance is proportional to the square of the time, then the distance in 9 seconds will be  (9/8)²  as long as the distance in 8 seconds.

(9/8)² = 1.265625

(64 ft) · (1.265625) = 81 ft.

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