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H2(g) + CO2(g) + 10 kcal H2O(g) + CO(g)

In another experiment involving the above reaction at 1,000°C, the equilibrium concentrations were found to be:

H2(g) = 2.0 moles per liter
H2O(g) = 4.0 moles per liter
CO2(g) = 5.0 moles per liter
CO(g) = 4.0 moles per liter

What is the equilibrium constant, Keq, for this reaction?

Respuesta :

The equilibrium contant for the reaction is 1.6. Solution: [H2]=2.0 mol/L [CO2]= 5.0 mol/L [H2O]= 4.0 mol/L [CO]= 4.0 mol/L K = [H2O][CO] / [H2][CO2] K = (4.0)(4.0) / (2.0)(5.0) K = 1.6 Ans [ =1.6 ]

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