Assuming the bus undergoes constant acceleration, it is given by:
a = (Vf-Vi)/Δt
a is the acceleration, Vf is the final velocity, Vi is the initial velocity, and Δt is the elapsed time.
Given values:
Vf = 90km/hr = 25m/s (the conversion rate from km/hr to m/s is 1/3.6)
Vi = 0m/s (starts from rest)
Δt = 8.0s
Plug in the values and solve for a:
a = (25-0)/8
a = 3.125m/s²
Round to 2 significant figures.
a = 3.1m/s²
