For this case we have by definition, that the area of a square base pyramid is given by:
[tex]V = \frac {L ^ 2 * h} {3}[/tex]
Where:
L: It's the side of the square base
h: It's the height of the pyramid
We have that[tex]L = 15 \ units[/tex], then [tex]L ^ 2 = 15 ^ 2 = 225 \ units ^ 2[/tex]
Substituting:
[tex]V = \frac {225 * 8} {3}\\V = 600 \ units ^ 3[/tex]
Finally, the volume of the pyramid is [tex]600 \ units ^ 3[/tex]
Answer:
[tex]600 \ units ^ 3[/tex]
