Answer:
0.373M
Explanation:
Given parameters:
Mass of NaOH given = 112g
Volume of solvent = 0.75L
Solution:
1....To solve this problem, we first find the number of moles of the solute using the expression below:
Number of moles = mass/molar mass
Solving:
Molar mass of NaOH
Atomic mass of Na = 23g
Atomic mass of O = 16g
Atomic mass of H = 1g
Molar mass = 23 + 16 + 1 = 40g/mol
Number of moles = 112/40 = 2.8mol
2..... From the number of moles of solute, we then evaluate the molarity of the solution that would be produced using the expression below:
Molarity = number of moles/Volume
Molarity = 2.8/0.75 = 0.373M
Answer : The molarity of NaOH is, 3.733 mole/L
Explanation : Given,
Mass of NaOH = 112 g
Molar mass of NaOH = 40 g/mole
Volume of solution = 0.750 L
Molarity : It is defined as the number of moles of solute present in one liter of solution.
In this question, the solute is NaOH.
Formula used :
[tex]Molarity=\frac{w_b}{M_b\times V}[/tex]
where,
[tex]w_b[/tex] = mass of solute NaOH = 112 g
[tex]M_b[/tex] = molar mass of solute NaOH = 40 g/mole
V = volume of solution = 0.750 L
Now put all the given values in the above formula, we get the molarity of the solution.
[tex]Molarity=\frac{112g}{40g/mole\times 0.750L}=3.733mole/L[/tex]
Therefore, the molarity of NaOH is, 3.733 mole/L
