Respuesta :
Answer:
The number of turns is 64.
Explanation:
Given that,
Magnetic field = 0.050 T
Area of coil = 100 cm²
Frequency = 60 Hz
Output voltage emf= 12 V
We need to calculate the number of turns
Using formula of induced emf
[tex]emf =NAB\omega[/tex]
[tex]N=\dfrac{emf}{A\times B\times2\pi f}[/tex]
[tex]N=\dfrac{12}{0.01\times0.050\times2\times3.14\times60}[/tex]
[tex]N =63.6 = 64\ turns[/tex]
Hence, The number of turns is 64.
Answer:
You need 63.66 turns.
Explanation:
The number of turns of a magnetic field is given by the following formula:
[tex]N = \frac{V}{S*T*2\pi f}[/tex]
In which N is the number of turns, V is the maximum output voltage, S is the area of the rotating coil, in square meters and T is the measure of the magnetic field and f is the frequency.
In this problem, we have that:
Suppose that you wish to construct a simple ac generator having an output of 12 V maximum when rotated at 60 Hz. This means that [tex]V = 12[/tex] and [tex]f = 60[/tex].
A uniform magnetic field of 0.050 T is available. This means that [tex]T = 0.050[/tex].
If the area of the rotating coil is 100 cm2, how many turns do you need?
This means that [tex]S = 0.01[/tex]m². So:
[tex]N = \frac{V}{S*T*2\pi f}[/tex]
[tex]N = \frac{12}{0.01*0.05*120\pi}[/tex]
[tex]N = 63.66[/tex]
You need 63.66 turns.
