An ambulance with a siren emitting a whine at 1570 Hz overtakes and passes a cyclist pedaling a bike at 2.45 m/s. After being passed, the cyclist hears a frequency of 1560 Hz. How fast is the ambulance moving? (Take the speed of sound in air to be 343 m/s.)

Respuesta :

Answer:

The speed of the ambulance is 4.66 m/s.

Explanation:

Given that,

The siren emitting a whine at 1570 Hz

The cyclist pedaling a bike at 2.45 m/s

The cyclist hears a frequency of 1560 Hz

We know that,

Speed of sound wave

[tex]v = 343\ m/s[/tex]

We calculate the speed of the ambulance

Using Doppler effect,

[tex]f'=f\times\dfrac{v+v_{o}}{v+v_{s}}[/tex]

Where,

[tex]f' [/tex]= frequency of ambulance siren

[tex]f [/tex]= cyclist hears the frequency

[tex]v_{s}[/tex]=speed of source

[tex]v_{v}[/tex]= speed of observer

Put the value in to the formula

[tex]v_{s}=f\times\dfrac{v+v_{o}}{f'}-v[/tex]

[tex]v_{s}=1570\times\dfrac{343-2.45}{1560}-343[/tex]

[tex]v_{s}=4.66\ m/s[/tex]

Hence, The speed of the ambulance is 4.66 m/s.