Answer:
Velocity is 3.02 m/s at an angle of 53.13° below X-axis.
Explanation:
Let unknown velocity be v.
Here momentum is conserved.
Initial momentum = Final momentum
Initial momentum = m x 6i + m x 0i = 6m i
Final momentum = m x (4.8cos 30 i + 4.8sin 30 j) + m x v = 4.16 m i + 2.4 m j + m v
Comparing
4.16 m i + 2.4 m j + m v = 6m i
v = 1.84 i - 2.4 j
Magnitude of velocity
[tex]v=\sqrt{1.84^2+(-2.4)^2}=3.02m/s[/tex]
Direction,
[tex]\theta =tan^{-1}\left ( \frac{-2.4}{1.8}\right )=-53.13^0[/tex]
Velocity is 3.02 m/s at an angle of 53.13° below X-axis.
