Answer:
Speration between the slits [tex]d=2.86\ \mu m[/tex]
Explanation:
Given that,
Wavelength of light, [tex]\lambda=612\ nm=612\times 10^{-9}\ m[/tex]
It is incident on a double slit produces a second-order maximum at an angle of 25 degree.
The condition for maxima is given as :
[tex]dsin\theta=m\lambda[/tex]
d = seperation between the slits
m = order, m = 2
[tex]d=\dfrac{m\lambda}{sin\theta}[/tex]
[tex]d=\dfrac{2\times 612\times 10^{-9}\ m}{sin(25)}[/tex]
d = 0.00000289
or
[tex]d=2.86\mu m[/tex]
So, the seperation between the silts is [tex]2.86\ \mu m[/tex]. Hence, this is the required solution.
