Answer:
The energy transferred is 2.93 MJ.
Explanation:
Given that,
Time = 1 h = 3600 s
Area[tex]A = 1.6\times4.00[/tex]
Width [tex]\Delta x=0.20 m[/tex]
Temperature [tex] T_{1}=20^{\circ}\ C[/tex]
[tex]T_{2}=5^{\circ}\ C[/tex]
For concrete wall,
The thermal conductivity
k = 1.7 W/mK
Using Fourier's law
[tex]Q=kA\dfrac{dt}{\Delta x}[/tex]
Where, A = area
[tex]\Delta x[/tex] = width
[tex]\Delta t[/tex] = change in temperature
k = thermal conductivity
Put the value into the formula
[tex]Q=1.7\times 1.6\times 4.00\times\dfrac{15}{0.20}[/tex]
[tex]Q=816\ W[/tex]
The energy transferred in 1 hour
[tex]E = Q\times t[/tex]
[tex]E=816\times3600[/tex]
[tex]E=2937600[/tex]
[tex]E = 2.93\times10^{6}\ J[/tex]
[tex]E = 2.93\ MJ[/tex]
Hence, The energy transferred is 2.93 MJ.
