A constant force of 120 N pushes a 55 kg wagon across an 8 m level surface. If the wagon was initially at rest, what is the final kinetic energy of the wagon?

Respuesta :

Answer:

The kinetic energy of the wagon is 967.0 J

Explanation:

Given that,

Force = 120 N

Mass = 55 kg

Height = 8 m

We need to calculate the kinetic energy of the wagon

Using newtons law

[tex]F = ma[/tex]

[tex]\dfrac{120}{55}=a[/tex]

[tex]a =2.2\ m/s^2[/tex]

Using equation of motion

[tex]v^2 =u^2+2as[/tex]

Where,

v = final velocity

u = initial velocity

s = height

Put the value in the equation

[tex]v^2=0+2\times2.2\times8[/tex]

[tex]v=5.93\ m/s[/tex]

Now, The kinetic energy is

[tex]K.E=\dfrac{1}{2}mv^2[/tex]

[tex]K.E=\dfrac{1}{2}\times55\times(5.93)^2[/tex]

[tex]K.E=967.0\ J[/tex]

Hence, The kinetic energy of the wagon is 967.0 J