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A 9800-N automobile is pushed along a level road by four students who apply a total forward force of 600 N. Neglecting friction, the acceleration of the automobile is: a) 0.0 m /s^2 b) 0.54 m/s^2 c) 0.6 m/s^2 d) 9.8 m/s^2

Respuesta :

Answer:

c).  [tex]a = 0.60 m/s^2[/tex]

Explanation:

As we know that weight of the automobile is given here

so weight = mass times gravity

[tex]W = mg[/tex]

[tex]9800 = m(9.8)[/tex]

[tex]m = 1000 kg[/tex]

now from Newton's law

[tex]F = ma[/tex]

[tex]600 = 1000 a[/tex]

[tex]a = \frac{600}{1000}[/tex]

[tex]a = 0.60 m/s^2[/tex]

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