Taking the speed of light in vacuum to be 3.000 x 10^8 m/s, find the speed of light in: a. air b. diamond c. crown glass d. water Data: nair =1.0003; ndiamond = 2.420; nwater = 1.340 ncrown glass = 1.500

Respuesta :

Explanation:

The speed of light in vacuum is, c = 3 × 10⁸ m/s

We have to find the speed of light :

(a) In air :

[tex]n_1_{air}=1.0003[/tex]

The equation of refractive index is given as :

[tex]n_1=\dfrac{c}{v_1}[/tex]

[tex]v_1=\dfrac{c}{n_1}[/tex]

[tex]v_1=\dfrac{3\times 10^8\ m/s}{1.0003}[/tex]

[tex]v_1=299910026.9\ m/s[/tex]

[tex]v_1=2.99\times 10^8\ m/s[/tex]

(b) In diamond :

[tex]n_2_{diamond}=2.42[/tex]

The equation of refractive index is given as :

[tex]n_2=\dfrac{c}{v_2}[/tex]

[tex]v_2=\dfrac{c}{n_2}[/tex]

[tex]v_2=\dfrac{3\times 10^8\ m/s}{2.42}[/tex]

[tex]v_2=123966942.1\ m/s[/tex]

[tex]v_2=1.23\times 10^8\ m/s[/tex]

(c) In crown glass :

[tex]n_3_{glass}=1.5[/tex]

The equation of refractive index is given as :

[tex]n_3=\dfrac{c}{v_3}[/tex]

[tex]v_3=\dfrac{c}{n_3}[/tex]

[tex]v_3=\dfrac{3\times 10^8\ m/s}{1.5}[/tex]

[tex]v_3=200000000\ m/s[/tex]

[tex]v_3=2\times 10^8\ m/s[/tex]

(4) In water :

[tex]n_4_{glass}=1.34[/tex]

The equation of refractive index is given as :

[tex]n_4=\dfrac{c}{v_4}[/tex]

[tex]v_4=\dfrac{c}{n_4}[/tex]

[tex]v_4=\dfrac{3\times 10^8\ m/s}{1.34}[/tex]

[tex]v_4=223880597.01\ m/s[/tex]

[tex]v_4=2.23\times 10^8\ m/s[/tex]

Hence, this is the required solution.