Answer:
Power, P = 112500 watts
Explanation:
It is given that,
Mass of the car, m = 1500 kg
Initial velocity of the car, u = 0
Final velocity of the car, v = 30 m/s
Time taken, t = 6 s
The minimum average power delivered by the engine is given by :
P = W/t
Where
W = work done
t = time taken
Work done = change in kinetic energy
So, [tex]P=\dfrac{\Delta K}{t}=\dfrac{\dfrac{1}{2}m(v^2-u^2)}{t}[/tex]
[tex]P=\dfrac{\dfrac{1}{2}\times 1500\ kg\times (30\ m/s)^2}{6\ s}[/tex]
P = 112500 watts
So, the minimum average power delivered by the engine is 112500 watts. Hence, this is the required solution.
