Answer:
195.5 mph, 49.85 degree
Explanation:
velocity of jet with respect to wind = 185 mph at 36 degree
V (j, w) = 185 (Cos 36 i + Sin 36 j) = 149.67 i + 108.74 j
velocity of wind with respect to ground = 47 mph at 120 degree
V(w,g) = 47 (Cos 120 i + Sin 120 j) = - 23.5 i + 40.70 j
Velocity of jet with respect to wind = velocity of jet with respect to ground - velocity of wind with respect to ground
V (j, w) = V (j, g) - V (w, g)
149.67 i + 108.74 j = V(j,g) + 23.6 i - 40.7 j
V(j,g) = 126.07 i + 149.44 j
Magnitude of velocity of jet with respect to wind
= [tex]\sqrt{126.07^{2}+149.44^{2}}[/tex] = 195.5 mph
Let it makes angle θ from + X axis
tan θ = 149.44 / 126.07 = 1.1185
θ = 49.85 degree
Answer:
Either 186.1 mph, 069° or 188.5 mph, 021°
Most likely 186.1 mph, 069°
Explanation:
I wanted to comment this but there's no way for me to comment :/
Both 186.1 mph, 021° and 195.6 mph, 069° are wrong.
Most likely 186.1 mph, 069° because 186.1 mph is what I got from my calculations.
Attached was my method. It's wrong tho so
