The Sun is orbiting around the entire galaxy such that it completes a full orbit once every 2 × 10 8 years. Using careful measurements of phenomena known as masers, we have acurately measured the distance to the center of the galaxy to be approximately 8 kpc (kiloparsecs). This is enough information to calculate our orbital speed. (Assume that the path the Sun takes is a circle which has a circumference of C = 2 ? R .) Report your answer in kilometers per second.

Respuesta :

Answer:

245.75 km/sec

Explanation:

We have given distance as 8 kilo parsec

We know that [tex]1\ kilo\ parsec=3.086\times 10^{16}km[/tex]

So 8 kilo parsec =8×3.086×[tex]10^{16}[/tex] km=2.469×[tex]10^{17}[/tex] km

We know that circumference = 2×Π×R

So circumference =2×3.14×2.469×[tex]10^{17}[/tex] = 15.50×[tex]10^{17}[/tex] km

We know that [tex]speed =\frac{distance}{time}[/tex]

We have given time =2×[tex]10^8[/tex] year

=2[tex]10^8[/tex]×365×24×60×60 sec

So [tex]speed=\frac{15.5\times 10^{17}}{6.30\times 10^{15}}=245.75\ km/sec[/tex]