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an object of mass 6000 kg rests on the flatbed of a truck. it is held in place by metal brackets that can exert a maximum horizontal force of 9000 N. when the truck is traveling 15 m/s, what is the minimum stopping distance if the load is not to slide forward into the cab?

Respuesta :

Answer:

minimum stopping distance will be d = 75 m

Explanation:

Maximum force exerted by the bracket is given as

F = 9000 N

now we know that mass of the object is

m = 6000 kg

so the maximum acceleration that truck can have is given as

[tex]F = ma[/tex]

[tex]9000 = 6000 a[/tex]

[tex]a = 1.5 m/s^2[/tex]

now for finding minimum stopping distance of the truck

[tex]v_f^2 - v_i^2 = 2a d[/tex]

[tex]0^2 - 15^2 = 2(-1.5) d[/tex]

[tex]d = 75 m[/tex]

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