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The human body can exhibit a wide range of resistances to current depending on the path of the current, contact area, and sweatiness of the skin. Suppose the resistance across the chest from the left hand to the right hand is 1.85 ✕ 106 Ω. (a) How much voltage is required to cause possible heart fibrillation in a man, which corresponds to 360 mA of direct current?

Respuesta :

Answer:

[tex]V = 6.66 \times 10^5 Volts[/tex]

Explanation:

As we know that resistance offered by the body from left hand to right hand is given as

[tex]R = 1.85 \times 10^6 ohm[/tex]

now the current flowing through the body is given as

[tex]i = 360 mA[/tex]

now in order to find out the potential difference across the hands that is applied is given by ohm's law

V = i R

[tex]V = (360 \times 10^{-3})(1.85 \times 10^6)[/tex]

[tex]V = 6.66 \times 10^5 Volts[/tex]

so the applied voltage across the hand must be given as above

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