A flexible loop has a radius of 10.5 cm and it is in a magnetic field of B = 0.117 T. The loop is grasped at points A and B and stretched until its area is zero. It takes 0.243 s to close the loop. What is the magnetic flux ΦB through the loop before it is streched? Tries 0/20 What is the magnetic flux through the loop after it is stretched? Tries 0/20 What is the magnitude of the average induced electromotive force ε in the loop during the stretching process?

Respuesta :

Explanation:

Given that,

Radius = 10.5 cm

Magnetic field = 0.117 T

Time = 0.243 s

After stretched, area is zero

(I). We need to calculate the magnetic flux through the loop before stretched

Using formula of magnetic flux

[tex]\phi=B\times A[/tex]

[tex]\phi=B\times \pi r^2[/tex]

Where, B = magnetic field

r = radius

Put the value into the formula

[tex]\phi=0.117\times3.14\times(10.5\times10^{-2})^2[/tex]

[tex]\phi=4.05\times10^{-3}\ Tm^2[/tex]

(II). We need to calculate the magnetic flux through the loop after stretched

[tex]\phi=B\times A[/tex]

Here, A = 0

[tex]\phi=0[/tex]

So, The magnetic flux through the loop after stretched is zero.

(III). We need to calculate the magnitude of the average induced electromotive force

Using formula of the induced electromotive force

[tex]\epsilon=-\dfrac{d\phi}{dt}[/tex]

[tex]\epsilon=-\dfrac{\phi_{after}-\phi_{before}}{t}[/tex]

[tex]\epsilon=-\dfrac{0-4.05\times10^{-3}}{0.243}[/tex]

[tex]\epsilon =16.67\times10^{-3}\ V[/tex]

Hence, This is the required solution.